source: trunk/SRC/ToBeReviewed/TRIANGULATION/triangule_c.pro @ 261

Last change on this file since 261 was 231, checked in by pinsard, 17 years ago

improvements/corrections of some *.pro headers

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RevLine 
[2]1;+
2;
[150]3; @file_comments
4; Construct the triangulation array.
[2]5;
[226]6; The idea is: construct a list of triangle which link points between them.
[150]7; This is automatically done by the function TRIANGULATE
8;  Here:
[226]9; we consider the fact that points are disposed on a grid (regular or not,
10; but not unstructured, that is to say that points are written following a
11; rectangular matrix). A easy way to do triangles between all points is then:
[2]12;
[163]13;     for each point (i,j) of the matrix -except those of the last line and of
[150]14;     the last column- we call rectangle (i,j) the rectangle made of the four
15;     points (i,j), (i+1,j), (i,j+1), (i+1,j+1). To trace all triangle, we just
16;     have to trace the 2 triangles contained in rectangles (i,j)
[2]17;
[150]18; We notice that each rectangle (i,j) have 2 diagonals (it is true... Make a
19; drawing to make sure!!), so there are two possible choice for each rectangle
20; we want to cut in 2 triangles...
[226]21;
[150]22; It is thanks to this choice that we will be able to trace coast with right
23; angles. At each angle of coast remarkable by the existence of an unique land
24; point or of an unique ocean point on one of the four summit of a rectangle (i,j),
25; we have to cut the rectangle following the diagonal passing by this point.
[226]26;
[150]27; @categories
[157]28; Graphics
[2]29;
[163]30; @param MASKENTREE {in}{optional}{type=2d array}
[226]31; It is a 2d array which will serve to mask the field we will trace after with CONTOUR,
[2]32; ...TRIANGULATION=triangule(mask)
[150]33; If this argument is not specified, the function use tmask
[2]34;
[150]35; @keyword BASIC
36; Specify that the mask is on a basic grid (use the triangulation for vertical cuts and hovmoellers)
[29]37;
[150]38; @keyword KEEP_CONT
39; To keep the triangulation even on the continents
[2]40;
[163]41; @keyword COINMONTE {type=array}
[226]42; To obtain the array of "ascending land corner" to be treated with
43; completecointerre.pro in the variable array instead of make it pass by the global
[150]44; variable twin_corners_up.
[29]45;
[163]46; @keyword COINDESCEND {type=array}
47; See COINMONTE
[2]48;
[150]49; @returns
50; res: tableau 2d (3,nbre de triangles).
[226]51; Each line of res represent indexes of points constituting summits of a triangle.
[150]52; See how we trace triangles in definetri.pro
[2]53;
[150]54; @uses
55; common.pro
56; different.pro
57; definetri.pro
[2]58;
[150]59; @restrictions
[226]60; Datas whose we want to do the contour must be disposed in a matrix.
61; On the other hand, in the matrix, the points's arrangement can not be
[150]62; irregular. If it is, use TRIANGULE.
[2]63;
[150]64; @history
[157]65; Sebastien Masson (smasson\@lodyc.jussieu.fr)
[150]66;                       26/4/1999
[2]67;
[150]68; @version
69; $Id$
[2]70;
[150]71; @todo
[226]72; seb L.267->268 je ne pense pas que ce soit ce que tu voulais dire mais
[150]73; c'est la traduction de ce qu'il y avait écrit. Correction si besoin.
[2]74;-
[231]75;
[29]76FUNCTION triangule_c, maskentree, COINMONTE = coinmonte, COINDESCEND = coindescend, BASIC = basic, KEEP_CONT = keep_cont
[114]77;
[150]78compile_opt idl2, strictarrsubs
[114]79;
[150]80tempsun = systime(1)            ; For key_performance
[29]81;---------------------------------------------------------
82@cm_4mesh
[150]83IF NOT keyword_set(key_forgetold) THEN BEGIN
[29]84@updatenew
[150]85ENDIF
[2]86;------------------------------------------------------------
[150]87; Is the mask given or do we have to take tmask?
[2]88;------------------------------------------------------------
89;
[150]90msk = maskentree
91taille = size(msk)
92nx = taille[1]
93ny = taille[2]
[2]94;
[150]95IF n_elements(keep_cont) EQ 0 THEN keep_cont = 1-key_irregular
[2]96;------------------------------------------------------------
[150]97if keyword_set(key_periodic)*(nx EQ jpi) $
[226]98  AND NOT keyword_set(basic) then BEGIN
[150]99    msk = [msk, msk[0, *]]
100    nx = nx+1
101ENDIF
[2]102;------------------------------------------------------------
[226]103; We will find the list of rectangles (i,j)(located by their left
104; bottom corner) we have to cut following a descendant diagonal.
[150]105; We will call this list : pts_downward
[226]106;
[150]107pts_downward = 0
[2]108
[150]109; We construct the test which allow to find this triangle :
[2]110;
111;
112;       shift(msk,  0, -1)------------shift(msk, -1, -1)
113;              |                             |
114;              |                             |
115;              |                             |
116;              |                             |
117;             msk---------------------shift(msk, -1,  0)
118;
[150]119sum1 = msk+shift(msk, -1, 0)+shift(msk, -1, -1)    ;points which surround the left top point.
120sum2 = msk+shift(msk, 0, -1)+shift(msk, -1, -1)    ;points which surround the right bottom point.
[2]121
122
[150]123tempdeux = systime(1)           ; For key_performance =2
124; The left top land point surrounded by ocean points
125liste = where( (4-sum1)*(1-shift(msk, 0, -1)) EQ 1 )
126if liste[0] NE -1 THEN pts_downward = [pts_downward,liste ]
127; The left top ocean point surrounded by land points
128liste = where( (1-sum1)*shift(msk, 0, -1) EQ 1)
129if liste[0] NE -1 THEN pts_downward = [pts_downward,liste ]
130; The right bottom land point surrounded by ocean points
131liste = where( (4-sum2)*(1-shift(msk, -1,  0)) EQ 1)
132if liste[0] NE -1 THEN pts_downward = [pts_downward,liste ]
133; The right bottom ocean point surrounded by land points
134liste = where( (1-sum2)*shift(msk, -1,  0) EQ 1)
135if liste[0] NE -1 THEN pts_downward = [pts_downward,liste ]
136undefine, liste
[2]137;
[150]138IF testvar(var = key_performance) EQ 2 THEN $
139  print, 'temps triangule: trouver pts_downward', systime(1)-tempdeux
[2]140;
[150]141if (NOT keyword_set(basic)) OR keyword_set(coinmonte) OR keyword_set(coindescend) then begin
142    tempdeux = systime(1)       ; For key_performance =2
143;2 land points in ascendant diagonal with 2 ocean points in descendant diagonal.
144    coinmont = where( (1-msk)*(1-shift(msk, -1, -1)) $
145                      *(shift(msk, 0, -1)*shift(msk, -1,  0) EQ 1) )
146    if coinmont[0] NE -1 THEN pts_downward = [pts_downward, coinmont]
[2]147;
[150]148    IF testvar(var = key_performance) EQ 2 THEN $
149      print, 'temps triangule: trouver coinmont', systime(1)-tempdeux
150    tempdeux = systime(1)       ; pour key_performance =2
[2]151;
[150]152    coindesc = where( ((1-shift(msk,  0, -1))*(1-shift(msk, -1, 0)) $
153                       *msk*shift(msk, -1, -1) EQ 1) )
[2]154;
[150]155;2 land points in descendant diagonal with 2 ocean points in ascendant diagonal.
156    IF testvar(var = key_performance) EQ 2 THEN $
157      print, 'temps triangule: trouver coindesc', systime(1)-tempdeux
[2]158;
[150]159ENDIF
[2]160;
[226]161if n_elements(pts_downward) EQ 1 then BEGIN
[150]162    tempdeux = systime(1)       ; For key_performance =2
[2]163;
[150]164    triang = definetri(nx, ny)
[2]165;
[150]166    IF testvar(var = key_performance) EQ 2 THEN $
167      print, 'temps triangule: definetri', systime(1)-tempdeux
168    coinmont = -1
169    coindesc = -1
[226]170ENDIF ELSE BEGIN
[150]171    tempdeux = systime(1)       ; For key_performance =2
172    pts_downward = pts_downward[1:n_elements(pts_downward)-1]
173    pts_downward = pts_downward[uniq(pts_downward, sort(pts_downward))]
[226]174; None rectangle can have an element of the last column or of the
[150]175; last line as left bottom corner.
176; so we have to remove these points if they has been selected in pts_downward.
[226]177    derniere_colonne = (lindgen(ny)+1)*nx-1
178    derniere_ligne = lindgen(nx)+(ny-1)*nx
[150]179    pts_downward =different(pts_downward,derniere_colonne )
180    pts_downward =different(pts_downward,derniere_ligne )
181    if (NOT keyword_set(basic)) OR keyword_set(coinmonte) OR keyword_set(coindescend) then begin
182        if coinmont[0] NE -1 then begin
[2]183            coinmont =different(coinmont,derniere_colonne )
184            coinmont =different(coinmont,derniere_ligne )
[150]185        endif
186        if coindesc[0] NE -1 then begin
[2]187            coindesc =different(coindesc,derniere_colonne )
188            coindesc =different(coindesc,derniere_ligne )
[150]189        endif
[226]190    ENDIF ELSE BEGIN
[150]191        coinmont = -1
192        coindesc = -1
[226]193    ENDELSE
[150]194    IF testvar(var = key_performance) EQ 2 THEN $
195      print, 'temps triangule: menage ds pts_downward coinmont et coindesc', systime(1)-tempdeux
[2]196;
[150]197    tempdeux = systime(1)       ; For key_performance =2
198    if  pts_downward[0] EQ -1 then triang = definetri(nx, ny) $
199    ELSE triang = definetri(nx, ny, pts_downward)
200    IF testvar(var = key_performance) EQ 2 THEN $
201      print, 'temps triangule: definetri', systime(1)-tempdeux
[226]202ENDELSE
[2]203;------------------------------------------------------------
[150]204; We delete land points which only contain land points.
[2]205;------------------------------------------------------------
206;
[226]207;
[150]208if (NOT keyword_set(basic)) AND (NOT keyword_set(keep_cont)) then begin
209    tempdeux = systime(1)       ; For key_performance =2
210; We delete rectangles which are entirely in the land.
211    recdsterre = where((1-msk)*(1-shift(msk, -1, 0))*(1-shift(msk, 0, -1))*(1-shift(msk, -1, -1)) EQ 1)
212    IF testvar(var = key_performance) EQ 2 THEN $
213      print, 'temps triangule: tous les recdsterre', systime(1)-tempdeux
[2]214
[150]215; We do an other sort :
216; We have to do not remove rectangles which only have one common summit.
[2]217; t1 = systime(1)
[150]218    indice = intarr(nx, ny)
219    trimask = intarr(nx, ny)
220    trimask[0:nx-2, 0:ny-2] = 1
[226]221    IF recdsterre[0] NE -1 then BEGIN
[150]222        tempdeux = systime(1)   ; For key_performance =2
223        indice[recdsterre] = 1
224        if NOT keyword_set(basic) then begin
225            vire1 = 0
226            vire2 = 0
227            while (vire1[0] NE -1 OR vire2[0] NE -1) ne 0 do begin
[226]228; Delete rectangles we have to remove from recsterre (in fact those we have
229; to keep although they are entirely in the land).
[150]230                vire1 = where( (indice*shift(indice, -1, -1) $
231                                *(1-shift(indice, 0, -1))*(1-shift(indice, -1, 0))*trimask) EQ 1)
[226]232                if vire1[0] NE -1 THEN BEGIN
[150]233                    indice[vire1] = 0
[2]234;               indice[vire1+nx+1] = 0
[150]235                endif
[226]236
[150]237                vire2 = where( ((1-indice)*(1-shift(indice, -1, -1)) $
238                                *shift(indice, 0, -1)*shift(indice, -1, 0)*trimask) EQ 1)
[226]239                if vire2[0] NE -1 THEN BEGIN
[150]240                    indice[vire2+1] = 0
[2]241;               indice[vire2+nx] = 0
[150]242                endif
243            endwhile
244            IF testvar(var = key_performance) EQ 2 THEN $
245              print, 'temps triangule: trier les recdsterre', systime(1)-tempdeux
246        endif
247        indice[*, ny-1] = 1     ; The last column and the last line
248        indice[nx-1, *] = 1     ; can not define any rectangle.
[2]249;
[150]250        tempdeux = systime(1)   ; For key_performance =2
251        recgarde = where(indice EQ 0)
252; We recuperate numbers of triangles we will keep.
253        trigarde = 2*[recgarde-recgarde/nx]
254        trigarde = transpose(temporary(trigarde))
255        trigarde = [trigarde, trigarde+1]
[226]256;
[150]257        triang = triang[*, temporary(trigarde[*])]
258        IF testvar(var = key_performance) EQ 2 THEN $
[29]259          print, 'temps triangule: virer les triangle de la liste', systime(1)-tempdeux
[150]260    endif
261endif
[226]262; print, 'temps tri triangles', systime(1)-t1
[2]263;------------------------------------------------------------
[226]264; When key_periodic equal 1, triang is a list of indexes's array which
[150]265; have a surplus column.
[226]266; We have to put it back to the initial matrix by putting indexes of
[150]267; the last column equal to these of the last column...
[2]268;------------------------------------------------------------
[150]269tempdeux = systime(1)           ; For key_performance =2
270if keyword_set(key_periodic)*(nx-1 EQ jpi) $
[226]271  AND NOT keyword_set(basic) then BEGIN
[150]272    indicey = triang/nx
273    indicex = triang-indicey*nx
274    nx = nx-1
275    liste = where(indicex EQ nx)
276    if liste[0] NE -1 then indicex[liste] = 0
277    triang = indicex+nx*indicey
278    nx = nx+1
279    if coinmont[0] NE -1 then begin
280        indicey = coinmont/nx
281        indicex = coinmont-indicey*nx
282        nx = nx-1
283        liste = where(indicex EQ nx)
284        if liste[0] NE -1 THEN indicex[liste] = 0
285        coinmont = indicex+nx*indicey
286        nx = nx+1
287    endif
288    if coindesc[0] NE -1 then begin
289        indicey = coindesc/nx
290        indicex = coindesc-indicey*nx
291        nx = nx-1
292        liste = where(indicex EQ nx)
293        if liste[0] NE -1 THEN indicex[liste] = 0
294        coindesc = indicex+nx*indicey
295        nx = nx+1
296    endif
297endif
298IF testvar(var = key_performance) EQ 2 THEN $
299  print, 'temps triangule: finitions', systime(1)-tempdeux
[2]300
301;------------------------------------------------------------
[150]302if keyword_set(coinmonte) THEN coinmonte = coinmont ELSE twin_corners_up = coinmont
303if keyword_set(coindescend) THEN coindescend = coindesc ELSE twin_corners_dn = coindesc
[2]304;------------------------------------------------------------
[150]305IF NOT keyword_set(key_forgetold) THEN BEGIN
[29]306   @updateold
[226]307ENDIF
[2]308
[226]309IF keyword_set(key_performance) THEN print, 'temps triangule', systime(1)-tempsun
[2]310
[150]311return, triang
[2]312
[226]313END
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